What are the problems of chiller purchase zui?
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What are the problems of chiller purchase zui?
(1) The location where the chiller is used. Generally, the first thing you need to know is that the customer who needs to purchase the chiller is equipped with the chiller. The place where the machine is installed is the place where Zui needs to ask. (2) Customer needs the chiller flow rate, temperature is how much, before following elaborate industrial chiller cooling capacity required temperature with the client how the method of calculation <br> <br> chiller cooling capacity is calculated, chiller refrigeration principle, 20kw It can be calculated in the following ways:
1: volume (liter) × liter temperature ÷ heating time (minutes) × 60 ÷ 0.86 (coefficient) = (w)
2: volume (ton or cubic meter) × liter temperature ÷ when heating (time) ÷ 0.86 (coefficient) = (kw)
Your data is calculated with the industrial chiller cooling capacity. The chiller cooling principle can be used for 4 hours 10000l × (15-7) ÷ 4h ÷ 0.86 = 23255w = 23.255kw 5 hours 10 tons × (15-7) ÷ 5h ÷0.86=18.604kw Compressor and chiller refrigeration convection condenser I don't know how to interpret it; that you can find online on the Internet, Shanghai Tianfeng Industrial Co., Ltd. (production chiller)
(3) Selection method of chiller energy conservation method Q=W in-W out Q: heat load (KW) W input: input power (KW) Example: 8KWW output: output power (KW) Example: 3KW
Example: Q=W in-W out=8-3=5(kw)
1. Time temperature rise method Q=Cp.rV△T/HQ: heat load (KW) Cp: constant pressure specific heat (KJ/kg.°C)......4.1868KJ/kg.°C
r: specific weight (Kg/m3)...1000Kg/m3V: total water quantity (m3) Example: 0.5m3
△T: water temperature difference (°C)...△T=T2-T1 Example:=5°CH: time (h) Example: 1h
Example: Q=Cp.rVâ–³T/H=4.1868*1000*0.5*5/3600=2.908(kw)
2. Temperature difference flow method Q=Cp.r.Vs.â–³T
Q: heat load (KW)
Cp: ​​constant pressure specific heat (KJ/kg. °C)......4.1868KJ/kg.°C
r: specific weight (Kg/m3)...1000Kg/m3Vs: water flow rate (m3/h) Example: 1.5m3/h
△T: water temperature difference (°C)...△T=T2 (in and out temperature)-T1 (inlet water temperature) Example:=10°C
Example: Q=Cp.r.Vs.â–³T=4.1868*1000*1.5*10/3600=17.445(kw)
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